3^2-(m+2)3+2m-1=0

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Solution for 3^2-(m+2)3+2m-1=0 equation: 



3^2-(m+2)3+2m-1=0

We add all the numbers together, and all the variables

2m-(m+2)3+8=0

We multiply parentheses

2m-3m-6+8=0

We add all the numbers together, and all the variables

-1m+2=0

We move all terms containing m to the left, all other terms to the right

-m=-2

m=-2/-1

m=+2

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